source: gtest-1.7.0/samples/sample1.cc@ 12761

Last change on this file since 12761 was 12746, checked in by hock@…, 11 years ago

integrated the Google Testing Framework (gtest)

and wrote an Hello World test, to ensure the framework is working..

File size: 2.4 KB
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[12746]1// Copyright 2005, Google Inc.
2// All rights reserved.
3//
4// Redistribution and use in source and binary forms, with or without
5// modification, are permitted provided that the following conditions are
6// met:
7//
8// * Redistributions of source code must retain the above copyright
9// notice, this list of conditions and the following disclaimer.
10// * Redistributions in binary form must reproduce the above
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12// in the documentation and/or other materials provided with the
13// distribution.
14// * Neither the name of Google Inc. nor the names of its
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16// this software without specific prior written permission.
17//
18// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
19// "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
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22// OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
23// SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
24// LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
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29
30// A sample program demonstrating using Google C++ testing framework.
31//
32// Author: wan@google.com (Zhanyong Wan)
33
34#include "sample1.h"
35
36// Returns n! (the factorial of n). For negative n, n! is defined to be 1.
37int Factorial(int n) {
38 int result = 1;
39 for (int i = 1; i <= n; i++) {
40 result *= i;
41 }
42
43 return result;
44}
45
46// Returns true iff n is a prime number.
47bool IsPrime(int n) {
48 // Trivial case 1: small numbers
49 if (n <= 1) return false;
50
51 // Trivial case 2: even numbers
52 if (n % 2 == 0) return n == 2;
53
54 // Now, we have that n is odd and n >= 3.
55
56 // Try to divide n by every odd number i, starting from 3
57 for (int i = 3; ; i += 2) {
58 // We only have to try i up to the squre root of n
59 if (i > n/i) break;
60
61 // Now, we have i <= n/i < n.
62 // If n is divisible by i, n is not prime.
63 if (n % i == 0) return false;
64 }
65
66 // n has no integer factor in the range (1, n), and thus is prime.
67 return true;
68}
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